Water and waste water treatment Assignment 02 Answers | January 2022 | NPTEL | Week 02 | The Today Blog

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Want to Know the Answers to NPTEL Water and waste water treatment 02? This article will tell you the answer to the National Programme on Technology Enhanced Learning (NPTEL) Course “Water and waste water treatment”. So read the complete article carefully.

About the Course: What is Water and waste water treatment

Waste water part of syllabus is covered from the headworks till the final Disinfection and Disinfectant removal,their design is also considered in detail. Water treatment portion covers the nitty gritty of treatment and the relevant aspects post treatment like residual removal. This course will allow the student to clear basics and concepts for further in depth learning.

CRITERIA TO GET A CERTIFICATE

Average assignment score = 25% of average of best 8 assignments out of the total 12 assignments given in the course.
Exam score = 75% of the proctored certification exam score out of 100

Final score = Average assignment score + Exam score

YOU WILL BE ELIGIBLE FOR A CERTIFICATE ONLY IF AVERAGE ASSIGNMENT SCORE >=10/25 AND EXAM SCORE >= 30/75. If one of the 2 criteria is not met, you will not get the certificate even if the Final score >= 40/100.

Certificate will have your name, photograph and the score in the final exam with the breakup.It will have the logos of NPTEL and IIT Roorkee.It will be e-verifiable at nptel.ac.in/noc.

Water and waste water treatment Assignment 02 Answers

Question 01 of 10

Select the correct statements regarding CSTRs and PFRs.

A. In a PFR, the contents are well stirred and uniform throughout.

B. In CSTR, at steady state the concentration changes with time.

C. In PFR, the concentration varies along the length of reactor.

D. PFRs are more efficient than CSTRs, at same hydraulic retention time.

C. In PFR, the concentration varies along the length of reactor.

D. D. PFRs are more efficient than CSTRs, at same hydraulic retention time.

Question 02 of 10

The following data pertain to a wastewater:Initial D.O. of mixture of sample and dilution water= 5.25 mg/LFinal D.O. of mixture of sample and dilution water= 3 mg/LThe BOD test is run by adding 2.00 mL of wastewater to the 300.0 mL BOD bottles. Assume dilution water has negligible oxygen demand.The BOD(in mg/L) of the wastewater is _______.

Correct Answer: 337.5

Question 03 of 10

For a waste, the 5-day BOD at 20°C is found to be 250 mg/L. For the same waste, 5-day BOD at 30°C will be

A. less than 250 mg/L

B. more than 250 mg/L

C. 250 mg/L

D. zero, as the bacteria cannot withstand such high temperatures.

B. more than 250 mg/L

Question 04 of 10

A wastewater sample has 4 days 20o C BOD value equal to the 75% of the ultimate BOD. The rate constant (base e) is________ per day.

Correct Answer: 0.15

Question 05 of 10

When wastewater is disposed into a running stream, four zones are formed. In which one of the following zones will the minimum level of dissolved oxygen be found?

A. Zone of degradation.

B. Zone of recovery.

C. Zone of clear water.

D. Zone of active decomposition.

D. Zone of active decomposition.

Common data for Q6&Q7:

In a batch reactor an experiment is run in lab to remove a toxic compound, TMDD by chemical treatment process. Initial concentration = 15mg/L TMDD Concentration after 30 mins = 2mg/L TMDD Assume that TMDD can be removed by a process which can be described by first order rate reaction (rloss = kCTMDD)

Question 06 of 10

Assuming steady state and treatment systems is plug flow, calculate the hydraulic retention time which would be required to achieve and effluent concentration of 1.5mg/L TMDD with the same initial concentration in the experiment. The hydraulic retention time is _________(in mins).

Correct Answer: 34.28

Question 07 of 10

The concentration of MgSO4 in a solution is 240g/L. Its concentration in Assuming steady state and treatment systems is completely mixed flow reactor, calculate the hydraulic retention time which would be required to achieve and effluent concentration of 1.5mg/L TMDD with the same initial concentration in the experiment. The hydraulic retention time is _________ (in mins).

Correct Answer: 134

Question 08 of 10

Select the correct statements regarding biochemical oxygen demand (BOD).

A. The BOD rate constant varies with temperature.

B. The time of self-purification in a stream does not depend on BOD rate constant of stream.

C. The second stage BOD is due to nitrification demand.

D. The ultimate BOD value of a waste remains the same at all temperatures.

A. The BOD rate constant varies with temperature.

C. The second stage BOD is due to nitrification demand.

D. e same at all temperatures.

Question 09 of 10

BOD is preferred to COD as an index of sewage concentration because________.

A. BOD represents both carbonaceous and nitrogenous organic matter while COD may indicate carbonaceous matter only.

B. BOD test is easier to perform and gives more reliable results.

C. BOD relates specifically to putrescible organic matter which is the most objectionable sewage constituent.

D. COD relates to the impurities which can only be removed by chemical treatment which is expensive.

A. BOD represents both carbonaceous and nitrogenous organic matter while COD may indicate carbonaceous matter only.

Question 10 of 10

The process in which a net fluid flow is in one direction and the compound

In a certain situation, waste water discharged into a river, which mixes with the river water instantaneously and completely. Following is the data available:Waste water DO = 2.5 mg/LDischarge rate = 1.20 m3/sRiver water DO = 7.8 mg/LRiver Flow rate = 8.70 m3/sTemperature = 20°CInitial amount of DO(in mg/L) in the mixture of waste and river shall be__________.

Correct Answer: 68.85

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